Area of a Hexagon: Formula & Examples

Let’s learn how to find the area of a hexagon.

What is a Hexagon?

A hexagon is a six-sided flat shape whose sum of interior angles is always 720°. If the hexagon has six equal angles and sides, it’s a regular hexagon. Otherwise, it’s an irregular hexagon. Regular polygons have apothem – the perpendicular distance from the hexagon’s center to the midpoint of one of its bases. 

Remember that all hexagons only have straight sides; no curves. Examples of hexagonal objects are honeycombs, metal nuts and bolts, and tabletops. 

Area of a Hexagon Using either the apothem or side length

There are several ways to compute the area of a regular hexagon. Let’s discuss some of them.

Related Reading: Area of a Trapezoid – Formula & Examples

Method #1: Splitting the regular hexagon into six (6) congruent and equilateral triangles.

The general formula for this is expressed by the equation:
A = [(33) / 2] s2
where A = Area of a hexagon; s = side length of the hexagon

Here’s how to use Method #1:

  1. Split the hexagon into six triangles that have equal sides and angles. 
  2. Find the area of one triangle.
  3. Multiply the area of that triangle by six to find the hexagon’s area.

Example Using Method #1:

Let’s work on this hexagon with 6cm side.

Hexagon for Example 1

One revolution means 360°, so diagonally splitting the hexagon gives us six triangles measuring 60° each (360 ÷ 6). Our goal is to find the area of one triangle first. For this example, let’s work on ∆CXD whose base is 6cm and angles are 60°. Take these steps to determine its area: 

Step 1. Bisect ∆CXD and name the new point G. Now we have ∆DXG, a special right triangle having a 30-60-90 angle and a base of 3cm (6cm÷2). Special right triangles have a side-length ratio of 1:2:3. 

Triangle ∆DXG

Step 2. Find the value of h or the length of ∆DXG’s longest side by following the ratio above. This will give us 33.

Step 3. We know that the value of h is also the height of ∆CXD, which is what we need to compute its area.

Triangle  ∆CXD

Step 4. Now, substitute the measurements (b = 6, h = 33) into the formula for a triangle’s area:
A = (bh) / 2. Remember that the h is also the apothem of the regular hexagon.
ACXD = (6)(33) / 2
=183 / 2
ACXD = 93cm2  
The area of ∆CXD is 93cm2.

Step 5. Multiply the area of ∆CXD by 6 to get the hexagon’s area. 
A⬡ABCDEF = 6 (93)
A⬡ABCDEF = 543cm2

Therefore, the area of the hexagon is 543cm2.

Method #2: Calculating using the regular hexagon’s perimeter and apothem

Use this formula to find the area of a hexagon using its apothem and perimeter:
A = (1 / 2) P • a
where P = Perimeter of the hexagon; a = the apothem.

Example Using Method #2:

Find the area of this hexagon with 64cm perimeter and 4cm apothem.

Solve the area of a hexagon using the apothem

Plug the measurements into the formula, then simplify. Don’t forget to include the unit.

A = (1 / 2) P • a
= (1 / 2) 64 • 4
=32 • 4
A = 128cm2

Therefore, the area of the hexagon is 128cm2.

Method #3: Calculating with the given apothem

What if you’re only given the apothem?

Example Using Method #3:

Find the area of this hexagon with 9cm apothem.

Hexagon and Triangle for Method 3

Step 1. Since the apothem is also the height of the special right triangle ∆DXG, find the length of its base (shortest leg) through dividing the apothem by 3 and multiplying their quotient by 3.
Base∆DXG = (9 / 3) 3 = 33

Step 2. Multiply the base of ∆DXG by 2 to get the base length of ∆DXC.
Base∆DXC = 2 (33) = 63

Step 3. Find the area of ∆DXC using its base and given apothem (height). 
A = (bh) / 2
A∆DXC = (63)(9) / 2
= 543 / 2
A∆DXC = 27 3 cm2

Step 4. Multiply the area of A∆DXC by 6 to find the hexagon’s area.
A⬡ABCDEF = 6 (273)
A⬡ABCDEF = 1623 cm2

Therefore, the area of the hexagon is 1623cm2.

Practice Finding the Area of a Hexagon:

#1. Find the area of a regular hexagon with an apothem of 6cm and side length of 9cm.

Finding the Area of a Hexagon Practice Problem #1 – SOLUTION:

Step 1. First, compute the perimeter using the side length.
A hexagon’s perimeter is the product of 6 and its side length:
P = 6s
= 6 (9)
P = 54cm

Step 2. Plug the apothem (a) and perimeter (P) into the formula, then simplify.
A = (1 / 2) P • a
= (1 / 2) 54 • 6
= 27 • 6
A = 162cm2

Therefore, the perimeter of the hexagon is 54cm and its area is 162cm2.

#2. Find the perimeter and area of a regular hexagon whose side length is 8cm.

Finding the Area of a Hexagon Practice Problem #2 – SOLUTION:

Step 1. Find the perimeter by multiplying the side length by 6. 
P = 6s
= 6 (8cm)
P = 48cm

Step 2. Compute the area by substituting the given side length into the formula:
A = [(33 ) / 2] • s2
= [(33 ) / 2] • 82
A = [(33 ) / 2] • 64
= (32) 33
A = 963cm2

Therefore, the perimeter of the hexagon is 48cm and its area is 963cm2.

Thank you for reading. We hope it’s effective! Always feel free to revisit this page if you ever have any questions about the area of a hexagon.

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